[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Sorting Question: Muenchian method? Substring in K
Oops... That should have been: not(substring(.,1,1) = substring(preceding-sibling::topic,1,1)) -Rob > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Robert Koberg > Sent: Friday, September 27, 2002 9:06 AM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: Sorting Question: Muenchian method? Substring in Key? > > > Hi, > > try passing it this way: > > <xsl:template match="topics"> > <div class="topics"> > <xsl:apply-templates select="topics/topic"> > <xsl:sort select="."/> > </xsl:apply-templates> > </div> > </xsl:template> > > <xsl:template match="topic"> > <xsl:variable name="previndex" select="position()-1"/> > <xsl:if test="not(substring(.,1,1) = > substring(/topics/topic[$previndex],1,1))"> > <div class="topicTitle"><xsl:value-of select="substring(.,1,1)"/></div> > </xsl:if> > <div class="topic"><xsl:value-of select="."/></div> > </xsl:template> > > best, > -Rob > > > > > -----Original Message----- > > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Thomas_M > > Sent: Friday, September 27, 2002 8:27 AM > > To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx' > > Subject: Sorting Question: Muenchian method? Substring in Key? > > > > > > Hello. This is my first XSLT project. I'm having trouble with grouping > > sorted items (seems to be a common theme). I have a XML file like this > > (simplified): > > > > <topics> > > <topic>Anteater</topic> > > <topic>Aardvark</topic> > > <topic>Beetle, Smaller European Elm Bark</topic> > > <topic>Beetle, American Burying</topic> > > <topic>Chimpanzee</topic> > > </topics> > > > > I would like the output to be sorted and grouped, with each group getting a > > heading: > > > > A > > Aardvark > > Anteater > > > > B > > Beetle, American Burying > > Beetle, Smaller European Elm Bark > > > > C > > Chimpanzee > > > > The corresponding part of my XSL is below. > > > > <xsl:template match="topics"> > > <table border="1"> > > <xsl:for-each select="topic"> > > <xsl:sort select="."/> > > <xsl:variable name="previndex" select="position()-1"/> > > <xsl:if test="not(substring(.,1,1) > > = substring(/topics/topic[$previndex],1,1))"> > > <tr><th><xsl:value-of select="substring(.,1,1)"/></th></tr> > > > > </xsl:if> > > <tr> > > <td><xsl:value-of select="."/></td> > > </tr> > > </xsl:for-each> > > </table> > > </xsl:template> > > > > As you can see, I'm comparing an element in a sorted node-set with a > > document-order node-set. This works only if the XML is pre-sorted. Is there > > a way to create the sorted node-set first, so that I can both traverse and > > use it in my test? > > > > I have seen a few examples of the Muenchian method, and it would seem this > > is another (perhaps better) way solve my problem. However, I've tried > > several times to implement it and can't seem to get it right (can you use a > > substring in a key?) > > > > Thanks for any insight, > > > > - Mark. > > > > -- > > Mark Thomas |_| > > Internet Systems Architect -+- > > User Technology Associates, Inc. | > > Thomas_M@xxxxxxx /-\ > > > > > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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