Re: for-each question

Regds
Vasu

From: Mike Brown <mike@xxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  for-each question
Date: Tue, 13 Aug 2002 11:04:06 -0600 (MDT)

Vasu Chakkera wrote:
> The problem is your template matches each book element.
> this is equivalent to a pseudo code
> for each book {
> The books are:
> Book-Name
> }

No it is not. "for each" is an instruction, an operation.
A template is a declaration, a definition.

A lot of XSLT newbies tend to be under the mistaken impression that
xsl:template causes something to happen. Your pseudocode reinforces this
confusion. They need to be told that it is actually the xsl:apply-templates
that causes nodes to be selected and processed.

I would tell him that his template was equivalent to defining
the following functions (Python style):

def handleAnyNode(node,result):                       # xsl:template
  if node.type == ELEMENT and node.name == 'book':    # match="book"
    handleBookNode(node,result)

def handleBookNode(node,result):
    frag = ResultTreeFragment()
    frag.append(TextNode('The Books Are:'))           # The Books Are:
    frag.child[0].append(Element('I'))                # <I>...</I>
    frag.child[1].append(TextNode(currentNodeName())) # xsl:value-of
    result.append(frag)

And that it was his <xsl:apply-templates select="book"> that was equivalent to
calling

for node in getAllNodesMatchingXpathExpression('child::book'):
  handleAnyNode(node,mainOutput)

   - Mike
____________________________________________________________________________
  mike j. brown                   |  xml/xslt: http://skew.org/xml/
  denver/boulder, colorado, usa   |  resume: http://skew.org/~mike/resume/

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