RE: alternating node type in a loop

If I understand you correctly, this should do it:

<xsl:apply-templates select="article">
<xsl:sort
select="concat(count(preceding-sibling::article[@type=current()/@type]),'::'
,@type)"/>
</xsl:apply-templates>

which will process the first article of type 1, then the first of type 2
(and potentially the first of type 3), then move on to the second of each
type, etc.

Note that an old version of MSXML that is in my copy of XMLSpy didn't
process this correctly, but Saxon 6.5.2 did.

Hope this helps,
David.
--
David McNally            Moody's Investors Service
Software Engineer        99 Church St, NY NY 10007 
David.McNally@xxxxxxxxxx            (212) 553-7475 


> -----Original Message-----
> From: Tyler Queen [mailto:xmllist@xxxxxxxxxxxx]
> Sent: Friday, July 12, 2002 3:21 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  alternating node type in a loop
> 
> 
> I want to loop through all the article nodes within a
> section element. The problem is I want to alternate the
> way they are looped by "type" going "1,2,1,2,1,2" and
> then when there aren't anymore to alternate through
> finish looping through the remaining nodes.
> Any Ideas?
> 
> This is the xml
> 
> <articles>
> 	<section>
> 		<article type="1">Article</article>
> 		<article type="2">Article</article>
> 		<article type="2">Article</article>
> 		<article type="1">Article</article>
> 		<article type="2">Article</article>
> 		<article type="1">Article</article>
> 		<article type="1">Article</article>
> 		<article type="1">Article</article>
> 	</section>
> <articles>
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


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