[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

file manipulation with recursion

Subject: file manipulation with recursion
From: Holmberg Rick-ra0119 <Rick.Holmberg@xxxxxxxxxxxx>
Date: Tue, 23 Jul 2002 06:10:33 -0700
file recursion
Hi all,
   I am new to XML/XSLT and have a file that I need to generate a smaller version of.  The file is of the format:

<hierarchy>
    <category>
      <id>0</id>
      <level>-1</level>
      <name>Cat1</name>
      <releaseLevel>Live</releaseLevel>
      <date>2002-02-25 12:29:46</date>
            <category>
                <id>13abc</id>
                <level>1</level>
                <name>Cat2</name>
                <releaseLevel>Live</releaseLevel>
                <date>2002-01-07 14:02:41</date>
                       <category>
                            <id>X12345</id>
                            <level>2</level>
                            <name>Cat3</name>
                            <releaseLevel>Live</releaseLevel>
                            <date>2002-07-11 14:52:06</date>
                      </category>
           </category>
    </category>
</hierarchy>
 
I need to have the output file be of the format
<hierarchy>
    <category>
      <id>0</id>
      <name>Cat1</name>
               <category>
                <id>13abc</id>
                <name>Cat2</name>
                       <category>
                            <id>X12345</id>
                            <name>Cat3</name>
                        </category>
               </category>
     </category>
</hierarchy>
 
I have to use recursion because I need the close each of the category tags in the output file.  I  am not sure how to iterate through these nodes.  I have tried several ways but have had no luck.  I dont' think that I can use a for-each because the depth of the categories will change and will not be known when I am processing the file.  This example shows the categories 3 deep but in actuality it will be anywhere from 4 to 10 deep.  Below is the latest version of what I have been trying.  Any help would be appreciated.  
 
 
<?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <xsl:output method="xml" indent="yes" /> 
 
<xsl:template match="hierarchy">
 <New_hierarchy>
  <xsl:apply-templates />
 </New_hierarchy>
   </xsl:template>
        
   <xsl:template name="category" match="category">
    <xsl:param name="index" select="'1'"/>
          <xsl:variable name="category" select="category"/>
          <xsl:variable name="relLevel" select="releaseLevel"/>
          <xsl:if test='$relLevel="Live"'>
           <category>
               <id><xsl:value-of select="category[$index]/id"/></id>
               <name><xsl:value-of select="category[$index]/name"/></name>
               <xsl:call-template name = "category">
                  <xsl:with-param name="index" select="$index+1"/>
               </xsl:call-template>      
           </category>  
          </xsl:if>
   </xsl:template>
 
   <xsl:template match="text()|@*">
   </xsl:template>
 
</xsl:stylesheet>

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.