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RE: basic xpath question

Subject: RE: basic xpath question
From: Stuart Brown <sbrown@xxxxxxxxxxxxx>
Date: Thu, 20 Jun 2002 10:25:01 +0100
basic xpath
Hi Dominic,

You can filter a template match by using attributes in a predicate (the
square brackets coming after the element name).

So, you can create two separate templates:

<xsl:template match="section[@id='para']">
  <p><xsl:apply-templates/></p>
</xsl:template>

<xsl:template match="section[@id='url']">
  <a href="{@url}"><xsl:apply-templates/></a>
</xsl:template>

You could also do this in one template, using <xsl:choose> to select the
different options:

<xsl:template match="section">
  <xsl:choose>
    <xsl:when test="@id='para'">
      <p><xsl:apply-templates></p>
    </xsl:when>
    <xsl:when test="@id='url'">
      <a href="{@url}"><xsl:apply-templates/></a>
    </xsl:when>
    <xsl:when test="@id='anAlternativeChoice'">
      <!-- Do whatever -->
    </xsl:when>
  </xsl:choose>
</xsl:template>

Hope this helps,

Stuart

> -----Original Message-----
> From: Hanlan, Dominic - Senior Developer [mailto:dhanlan@xxxxxxxxx]
> Sent: 20 June 2002 10:11
> To: 'XSL-List@xxxxxxxxxxxxxxxxxxxxxx'
> Subject:  basic xpath question
> 
> 
> Hi,
> 
>  I have an xml document to be styled, if I have a construct such as 
> 
> <section id="para">this is text <section id="url"
> url="http://xx.yy.zz">which is to be a link</section></section>
> 
> How do I, in xslt, recognise the "url" tag within the "para" 
> tag, such that
> I could ouput someting like
> 
> <p>this is test <a href="http://xx.yy.zz">which is to be a 
> link</a></p>
> 
> Regards
> 
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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