[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re:Problem w/ call-template
Thank you both of you for quickly spotting the problem. I closed the template in the wrong place as Peter pointed out. Nilesh explicitly spelled it out for me. :>))) I have made the correction; that fixed the problem. However, somehow, w/ the existing logic, "originalString" doesn't seem to be passed correctly. It prints out correctly the "String" where it was selected ( before calling the template lastSubString. However, the result is empty since the "originalString" is empty in the template "lastSubString". How do I print out the "$originalString" in the location marked ***DEBUG: for debugging? Thanks, Kim > Date: Thu, 30 May 2002 07:41:19 +0000 > From: "NILESH PATEL" <jayganesh786@xxxxxxxxxxx> > Subject: Re: Problem w/ call-template > > Hi Kim, > > I think even then it will still complain about template name do not match or > something. I think your xsl fragment should look like this. Correct me if I > am wrong, as I am not really a master in xsl. > > <xsl:template match="String"> > [...] > <xsl:call-template name="lastSubString"> > <xsl:with-param name="originalString" select="."/> ***DEBUG1: > </xsl:call-template> > </xsl:template> > > <xsl:template name="lastSubString"> > <xsl:param name="originalString"/> ***DEBUG2: > <xsl:choose> > <xsl:when test="contains($originalString,',')"> > <xsl:call-template name="lastSubString"> > <xsl:with-param name="originalString" > select="substring-after($originalString,',')"/> > </xsl:call-template> > </xsl:when> > </xsl:choose> > Last substring: <xsl:value-of select="$originalString"/> > </xsl:template> > > See if this works, which I am preety sure(99.9%) will work. Let me know the > resultplease so I can judge myself. > > Thanks, kepp the good work going. > > Nilesh Patel > > > >From: Peter Davis <pdavis152@xxxxxxxxx> > >Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > >To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > >Subject: Re: Problem w/ call-template > >Date: Wed, 29 May 2002 19:53:13 -0700 > > > >-----BEGIN PGP SIGNED MESSAGE----- > >Hash: SHA1 > > > >On Wednesday 29 May 2002 16:11, Kim wrote: > > > Hi, > > > > > > I got an error msg: Could not find template named: "lastSubString". It > >is > > > from the "***" line. What am I missing here? I checked the spelling; > >it > > > is fine. > >... > > > </xsl:template> > > > </xsl:template> > > > >You have defined the "lastSubString" template *within* another template. > >Really you shouldn't have gotten this far -- <xsl:template> must be a > >top-level element (that is, a child of <xsl:stylesheet>). Simply move the > >"lastSubString" template outside of the other template and it should work. > > > >- -- > >Peter Davis ===== Kim ************************* May the force be with you. ************************* __________________________________________________ Do You Yahoo!? Yahoo! - Official partner of 2002 FIFA World Cup http://fifaworldcup.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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