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RE: removing nesting in data structure

Subject: RE: removing nesting in data structure
From: "Andrew Welch" <awelch@xxxxxxxxxxxxxxx>
Date: Mon, 20 May 2002 12:46:01 +0100
RE:  removing nesting in data structure
Ok,

Ive found a problem already... for some reason it applies subpara3
twice.  Why is this?  When I use Xselerator's debugger I can see that
when Im matching say subpara1 the line

<apply-templates select="subpara1|subpara2|subpara3"/>

matches both subpara2 and subpara3 - which is correct as it is creating
a union of the matches.   What select should I use instead?  Will I need
to split up the template?

cheers
andrew

=====xml=====
<?xml version="1.0"?>
<root>
  <para0>
    <para>para 0</para>
    <subpara1>
      <para>subpara 1</para>
      <subpara2>
        <para>subpara 2</para>
        <subpara3>
          <para>subpara 3</para>
        </subpara3>
      </subpara2>
    </subpara1>
  </para0>
</root>

====xslt======
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:msxsl="urn:schemas-microsoft-com:xslt"
                version="1.0">

<xsl:template match="/">
  <xsl:apply-templates/>
</xsl:template>


<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>


<xsl:template match="para0|subpara1|subpara2|subpara3">
  <xsl:copy>
    <xsl:apply-templates
select="*[not(subpara1)][not(subpara2)][not(subpara3)]"/>
  </xsl:copy>
  <xsl:apply-templates select="subpara1|subpara2|subpara3"/>
</xsl:template>

</xsl:stylesheet>




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