Re: Filtering nodes

<xsl:template match="Record">
  <xsl:copy>
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

<!-- empty records -->
<xsl:template match="Record[not(@*)]">
  <xsl:apply-templates/>
</xsl:template>

<!-- records with leaves -->
<xsl:template match="Record[Leaf]">
  <Leaf Name="{@Name}"/>
</xsl:template>

Hello group,

I have a simple XML like

 <Root>
     <Record Name="R1">
	<Record Name="L1">
		<Leaf Name="text"/>
	</Record>
	<Record>
		<Record Name="L2">
			<Leaf Name="text"/>
		</Record>
	</Record>
	<Record Name="R2">
		<Record>
			<Record>
				<Record>
					<Record Name="LL1">
						<Leaf Name="text"/>
					</Record>
					<Record Name="LL2">
						<Leaf Name="text"/>
					</Record>
				</Record>
			</Record>
		</Record>
	</Record>
 </Root>

To transform it to a simple structure like
<Record Name="R1">
	<Leaf Name="L1"/>
	<Leaf Name="L2"/>
	<Record Name="R2>
		<Leaf Name="LL1"/>
		<Leaf Name="LL2"/>
	</Record>
</Record>

Could any one suggest ways to filter the dummy record nodes under R1 and R2
and display the Leaf nodes under R1 and R2.

For displaying the field nodes under a specific record I used the keys
function to select the "Record" elements with a "Leaf" element and having
attribute "Name" value "text" as follows:
 <xsl:key name="leaf-nodes" match="Record" use="Leaf/@Name"/>

This is fine for R2 but fails for R1 in which case it is diplaying all the
fields in R2 also.

Could some correct the keys expression/suggest a better way for doing this.

Thanks and regards,
Suresh