[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: accessing last element of node set passed as param

Subject: Re: accessing last element of node set passed as parameter
From: "J.Pietschmann" <j3322ptm@xxxxxxxx>
Date: Mon, 20 May 2002 23:44:17 +0200
Re:  accessing last element of node set passed as param
paul morgan wrote:
I'm trying to figure out how to access the last element
> of a node set which is passed as a parameter to a template.

For example, with:


    <xsl:template match="FOO">
        <xsl:param  name="result"  select="/.." />
        <xsl:variable  name="prior"  select="$result/BAR[last()]" />
        <!-- Something done it is -->
    </xsl:template>

if "FOO" is matched, and the parameter, "result", is assigned the node set

<BAR i=1/><BAR i=2/><BAR i=3/>

what expression would I need to access the last "BAR" element

You are trying to select the last of BAR *children* of anything in the passed node set. Try select="$result[last()]", though I'm not sure it'll work either.

J.Pietschmann


XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list



Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.