RE: xsl:sort question

It works. Thanks a lot Joerg.

Thanks,
Priya

-----Original Message-----
From: Joerg Heinicke [mailto:joerg.heinicke@xxxxxx]
Sent: Friday, April 26, 2002 11:15 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  xsl:sort question


Hello Priya,

your approach is correct, but incomplete. When you sort for @WellName, 
then the nodes will be selected alphabetically. The second sort will 
only have an effect, if two nodes are equal in the first sort criteria.

What you need:

<xsl:sort select="substring(@WellName,1,1)"/>
<xsl:sort select="substring(@WellName,2)" data-type="number"/>

Regards,

Joerg

> I am not getting the above result with my XSL. What is the problem ?
> 	<xsl:template match="ANALYSISRESULTS">
> 		<xsl:variable name="wells" select="//WELL"/>
> 		<xsl:for-each select="$wells">
> 			<xsl:sort select="@WellName"/>
> 			<xsl:sort select="substring(@WellName,2)"
> data-type="number"/>
> 		 	<xsl:for-each select="@*">
> 				<xsl:value-of select="."/> <xsl:value-of
> select="$tab"/>
> 		 	</xsl:for-each>
> 		 	<xsl:value-of select="$newline"/>
> 		</xsl:for-each>
> 	</xsl:template>
> 
> Thanks,
> Priya
> X 323


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