RE: Design problem - print header information only if

Hi Ming-tzung,

Try this:

<xsl:template match="Header">
<xsl:if test="contains(Detail, 'sometext')">
<xsl:apply-templates/>
</xsl:if>
</xsl:template>

Where 'sometext' is the text match for your satisfaction criteria.

Zarella

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Dung,
> Ming-tzung
> Sent: Wednesday, April 24, 2002 12:37 PM
> To: XSLT List (E-mail)
> Subject:  Design problem - print header information only if some
> element exists in the detail.
>
>
> Hi,
>    I have an input XML source as the following:
> ....
> <Header>
> ....
> <!-- could have multiple detail information. -->
> <Detail>..<Detail>
> </Header>
>     I need to output the content of the Header ONLY IF certain information
> exists in the detail. (Let us called this as the satisfied
> Detail). Besides,
> each satisfied Detail needed to print out after the Header. The design
> forces also includes that the testing condition may grow complex in the
> future.
> I guess that I have two ways in solving this; however, none of
> the solution
> I come up with is not a good solution.
> <1>
>   Pass the document to one XSL for filtering out the 'unsatisfied' Detail.
> Then pass the filtered XML to the XSLT again for  output.
>   ==>Disadvantage - the performance.
> <2>
>    Use <xsl:for-each > to select the satisfied Detail node.
>    ==>Disadvantage: If the condition grows complex, I am not sure whether
> the select attribute within the <xsl:for-each> can fulfill the needs. In
> addition, If there are multiple detail, how I can print the Detail element
> once only within the <xsl:for-each> body? (The only solution for
> this I can
> see is have two <xsl:for-each>. The first one is check there is any Detail
> satisfied. If yes, print the header information. Then the second print out
> the detail. )
>
>   Thanks in advance!!
>
>
> Ming-tzung Dung
>
>
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>


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