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RE: Looping and assigning into variable

Subject: RE: Looping and assigning into variable
From: "Venkateshwar Bommineni" <vbommineni@xxxxxxxxxx>
Date: Thu, 28 Mar 2002 11:31:19 -0500
concatenating 2 variable in xsl
Hi Jeni,
 Actually I had to concatenate 2 child elements for each header and
concatente result with previous one. So according to your suggestion I
have to do like, 

  <Comments>
    <xsl:for-each select="Header">
      <xsl:value-of select="concat(RefNo,Comment)" />
    </xsl:for-each>
  </Comments>

Is that correct? So Is it good way to apply template on same match,
mutiple times in the same document as :

   <xsl:for-each select="Header">
      -- do some thing --
   </xsl:for-each>

   <Comments>
   	<xsl:for-each select="Header">
     	    <xsl:value-of select="concat(RefNo,Comment)" />
    	</xsl:for-each>
   </Comments>	

I had the impression that XSLT processor parses input XML in SAX manner
thus it matches an Element and applies relavant template only once. Am I
wrong?

Thanks for your help
>>VENKAT

-----Original Message-----
From: Jeni Tennison [mailto:jeni@xxxxxxxxxxxxxxxx]
Sent: Thursday, March 28, 2002 11:12 AM
To: Venkateshwar Bommineni
Cc: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  Looping and assigning into variable


Hi Venkat,

> Basically Each 'Header' element has 1 'Comment' child element in it.
> So I have to loop through all headers and finally get the complete
> list of concatenated 'Comment's

Just do:

  <Comments>
    <xsl:for-each select="Header">
      <xsl:value-of select="Comment" />
    </xsl:for-each>
  </Comments>

In other words, construct the concatenated list of comments when you
need the concatenated list of comments, don't try to build it at the
same time as doing something else. It's very hard doing two things at
once with XSLT.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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