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RE: XSL menu using multiple row HTML table

Subject: RE: XSL menu using multiple row HTML table
From: Lea Allison <Lea.Allison@xxxxxxxxxxxxxx>
Date: Thu, 28 Feb 2002 07:26:59 +0100
xsl menu
WHHEEYYY!

Thanks. I didn't know you could use select on for each statements.

I'm going to stop working for 5 minutes now and have a cuppa coffee.

Lea

-----Original Message-----
From: Joerg Heinicke [mailto:joerg.heinicke@xxxxxx]
Sent: woensdag 27 februari 2002 22:22
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  XSL menu using multiple row HTML table


Hello Lea,

you may not do the for-each about all elements, but about every 8th (or
$max'th) element. If you know them you have still to loop over the current
element and the next 7 ones (or $max -1).

<xsl:for-each select="*[position() mod $max = 1]">
    <tr>
        <xsl:for-each select=" . | following-sibling::*[position() &lt;
$max]">
            <xsl:apply-templates select="NAME"/>
        </xsl:for-each>
    </tr>
</xsl:for-each>

Regards,

Joerg

----- Original Message -----
From: "Lea Allison" <Lea.Allison@xxxxxxxxxxxxxx>
To: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, February 27, 2002 4:26 PM
Subject:  XSL menu using multiple row HTML table


> Hello
>
> I've have a problem that has had me up for 2 days, and I've learnt alot,
but
> now my head is just busting... I need help!
>
> I am trying to create a template that will convert my XML menu doc
(extract
> below) into an HTML menu. The menu I wont is the horizontal type, and the
> real problem I have is selecting the number of menu items per row.
>
> I cannot figure out how to get the stylesheet to read the first X number
of
> items in, then start a new row, and another until complete. I cannot use
> "for-each" to split the <TR> and </TR> tags without creating bad XML...
and
> using named templates recursively loses me when one row is complete and I
> want to continue my proccessing on the newxt row.
>
> OK, here is a snippet of the source XML:
>
> <LIBRARY>
> <WEB>
> <HOME isCategory="yes">
> <NAME>Home</NAME>
> <DESCRIPTION>Virgin Home page</DESCRIPTION>
> </HOME>
> <VIRGININFO isCategory="yes" icon="" hide="no">
> <NAME>Virgin Info</NAME>
> <DESCRIPTION>Virgin commercial
> information</DESCRIPTION>
> <CORPORATE isCategory="yes" icon=""
> hide="no">
> <NAME>Corporate</NAME>
> <DESCRIPTION>Corporate
> information</DESCRIPTION>
> </CORPORATE>
> </VIRGININFO>
> ... ...
> <TEST>
> <NAME>LEA</NAME>
> </TEST>
> </WEB>
> </LIBRARY>
>
> I don't think this is the best way for trying to do this job, but the
reason
> is that I'm using XPath from my app to access these items... I'll get
round
> that, but here's my problem. This what I've got after 2 days deleting and
> re-writing so please ignore this if it is completly wrong:
>
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0"
>    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:output method="html"/>
>
> <xsl:template match="/">
>
> <HTML><BODY>
> <TABLE border="1" width="100%">
>
> <xsl:apply-templates select="LIBRARY/WEB" />
>
> </TABLE>
> </BODY>
> </HTML>
>
> </xsl:template>
>
> <xsl:template match="LIBRARY/WEB">
>
> <xsl:param name="max">8</xsl:param> <!-- MAX ITEMS PER TABLE ROW -->
>
> <TR>
> <xsl:for-each select="*">
> <xsl:choose>
> <xsl:when test="position() -1 &lt; $max">
>
> <xsl:apply-templates select="NAME" />
>
> </xsl:when>
> </xsl:choose>
> </xsl:for-each>
> </TR>
> <!-- xsl:apply-templates select="//LIBRARY/WEB" /
> --> <!-- !!!! err ? -->
> </xsl:template>
>
> <xsl:template match="NAME">
> <TD><B><xsl:apply-templates /></B></TD>
> </xsl:template>
>
> <xsl:template match="*" />
> </xsl:stylesheet>
>
>
> Cheers!!
>
> Lea
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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