Re: alternate row color in a table

thanks but,


this doesn't work in this case:

***XML***
<?xml version="1.0" encoding="UTF-8"?>
<?xml:stylesheet type="text/xsl" href="simple4.xsl"?>
<data>
<info>aaaaa</info>
<info>bbbbb</info>
<grinfo><info>ccccc</info></grinfo>
<grinfo><subinfo>blabla</subinfo><info>ddddd</info></grinfo>
</data>

***XSL***
<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:output method="html"/>

<xsl:template match="info">
<tr>
<xsl:if test="(position() mod 2 = 1)">
<xsl:attribute name="bgcolor">#EEEEFF</xsl:attribute>
</xsl:if>
<td>
<xsl:apply-templates/>
</td></tr>
</xsl:template>

<xsl:template match="data">
<table><xsl:apply-templates/></table>
</xsl:template>

<xsl:template match="grinfo">
<xsl:apply-templates/>
</xsl:template>


</xsl:stylesheet>

the row with ccccc and the row with ddddd have the same bgcolor
using position() in this case seems to work just with siblings.

S.T.






------------------------------------------------------------------------------------------




>>> vdv@xxxxxxxxxxxx 02/14/02 03:17 >>>
Joerg Heinicke wrote:
> I don't know your XSLT-code exactly, so that I can only recommend you 
> the general way:
> 
> <xsl:attribute name="class">
>      <xsl:choose>
>          <xsl:when test="position() mod 2 = 1">class1</xsl:when>
>          <xsl:otherwise>class2</xsl:otherwise>
>      </xsl:choose>
> </xsl:attribute>

Or (along the same line) simply define the CSS styles for "row0" and 
"row1" and write:

   <tr class="row{position() mod 2}">
     .../...
    </tr>

:)

Eric
-- 
See you in Seattle.
                                        http://knowledgetechnologies.net/ 
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