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Re: outputting an <a href> with a URL which contains "

Subject: Re: outputting an <a href> with a URL which contains "&func"
From: "Joerg Heinicke" <joerg.heinicke@xxxxxx>
Date: Mon, 21 Jan 2002 23:56:46 +0100
contains url
In XML you have to replace & by &amp; and < by &lt; . Then you don't need
these constructs with disable-output-escaping (avoid this in general!!) and
CDATA.

Regards,

Joerg
----- Original Message -----
From: "Saverio Perugini" <sperugin@xxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, January 21, 2002 11:36 PM
Subject:  outputting an <a href> with a URL which contains "&func"


> Hello,
>
> I'm trying to output an <a href> from an XSL template.
> The value of the href attribute is a URL which contains the string
> ``&func''
>
> The following results in an error regarding the reference to entity
"func".
> The error states that the reference must end with the ';' delimiter.
>
> <a><xsl:attribute name="href"><xsl:text
disable-output-escaping="yes">http://....?dtype=C&func=front&state=&style=">
</xsl:text></xsl:attribute></a>
>
> I have been able to circumvent this error with the following code.
>
> <a><xsl:attribute name="href"><xsl:text
disable-output-escaping="yes"><![CDATA[http://....?dtype=C&func=front&state=
&style=]]></xsl:text></xsl:attribute>
>
> Is this the correct method to achieve my desired result?
>
> Thank You,
>
> Saverio Perugini
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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