RE: RE: Postional predicates de-mystified

Mike wrote:
> to obtain nodes in non-document order. For example the expression
> 
>   for $i in 1 to count(ancestor::*) return ancestor::*[$i]
> 
> will return a sequence containing all the ancestors of the 
> context node, in
> reverse document order.

and 
<xsl:value-of select=" for $i in 1 to count(ancestor::*) 
   return name((ancestor::*)[$i])" separator = "/"/> 

Provides the 'path' to the current node! Pretty neat.
(or should I be saying a document order sequence?)

Seems like Evans (sorry XSLT 1.0) ( ) pairing still works as he
described.

Worked for me Evan :-)

Regards DaveP

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