[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: XPath expression to derive list of distinct elemen
> From: David Carlisle <davidc@xxxxxxxxx> > doesn't > select="$x//*[not(following::*[name()=name(current())])]" > select all the element nodes in $x that are the last occurrence of an > element of that name? As far as i can see not, unless you redefine the current() function. Why not using the Muenchian method? <xsl:key name="sibling-names" match="*" use="concat(generate-id(..),'#',name())"/> ... select="*[generate-id()=generate-id(key(generate-id(..),'#',name())[1])]" Untested. There are some obvious optimizations. I'm not sure whether this is what the original poster wanted but HTH anyway. I also hope Jeni is absorbed with other stuff enough that i can beat her this time... :-) J.Pietschmann XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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