[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Template match via xsl:param

Subject: Template match via xsl:param
From: Mario Lang <mlang@xxxxxxxxxxx>
Date: 14 Jan 2002 22:03:40 +0100
xsl param match
Hello.

I am trying to write some generic stylesheets which I can stack in filterproxy.

>From the archive/FAQ I figure that this isnt as easy as one may think, but
I couldnt find a simple example which illustrates how to do it right.

So, here is what I am trying to do:

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
  <xsl:output method="html" indent="yes"
              encoding="iso8859-15"/>
  <xsl:param name="path"></xsl:param>
  <xsl:include href="identity.xsl"/>

  <xsl:template match="$path"/>

</xsl:stylesheet>

Can anyone give me a simple example on how to achieve this without
genereting the xsl file on the fly?

-- 
CYa,
   Mario <mlang@xxxxxxxxxxx>

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.