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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Newbie: template matching and multiple document output
 Dear List,
This is my second attempt to post this problem. I have read all recent posts
on template matching but can't get the answer.
The aim is to convert the xml file below into: 1) an index page in html,
with links to all sub-files - this uses template "id" and works fine, 2) one
html page for each "part", with the file name MSC01.html, MSC02.html, etc,
containing just the text from that part. The best I can get is one html
page, named MSC01.html, which contains the text from all the "parts".
I am using Instant Saxon 6.5 to perform the transformation.
Many thanks,
Steve Perriman
Intranet/Internet Support Technician
South Trafford College
PS: If this one doesn't arrives in plain text, I shall have to use a
different mail server.
----------------------------------------------------------------------------
---
xml file
----------------------------------------------------------------------------
---
<document>
<part id = "MSC01">
<par kind = "id">MSC01</par>
<par kind = "Section">Some text Some text Some text </par>
<par kind = "Title">Some text Some text Some text </par>
<par kind = "Leaflet_Sub-heading">Who is the programme
for?</par>
<par kind = "Leaflet_text">Some text Some text Some text
</par>
<par kind = "Leaflet_Sub-heading">How long does it take to
complete?</par>
<par kind = "Leaflet_text">Some text Some text Some text
</par>
</part>
<part id = "MSC02">
<par kind = "id">MSC02</par>
<par kind = "Section">Some text Some text Some text </par>
<par kind = "Title">Some text Some text Some text </par>
<par kind = "Leaflet_Sub-heading">Who is the programme
for?</par>
<par kind = "Leaflet_text">Some text Some text Some text
</par>
<par kind = "Leaflet_Sub-heading">How long does it take to
complete?</par>
<par kind = "Leaflet_text">Some text Some text Some text
</par>
</part>
</document>
----------------------------------------------------------------------------
---
xsl stylesheet
----------------------------------------------------------------------------
---
<?xml version="1.0"?>
<xsl:stylesheet version="1.1"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="Windows-1252" />
<xsl:param name="dir">directory</xsl:param>
<xsl:variable name="file" select="system-property('file.separator')" />
<xsl:template match="/">
<xsl:call-template name="part" />
</xsl:template>
<xsl:template name = "part" match = "/document/part">
<html>
<head>
</head>
<body>
<xsl:call-template name="id" />
<xsl:call-template name="document" />
</body>
</html>
</xsl:template>
<xsl:template name="document" match="//@id">
<xsl:for-each select = "part">
<xsl:document href = "{//@id}.html" method = "html">
<html>
<head></head>
<body>
<table border="0" width="100%" cellspacing="0"
cellpadding="2">
<xsl:element name="tr">
<xsl:element name="td">
<xsl:call-template name= "kind" />
<xsl:value-of disable-output-escaping="yes"
select="text()" />
</xsl:element>
</xsl:element>
</table></body>
</html>
</xsl:document>
</xsl:for-each>
</xsl:template>
<xsl:template name="kind" match="/@kind">
<xsl:for-each select="/*[@kind != '']">
<xsl:element name="span">
<xsl:attribute name = "class" >
<xsl:value-of select = "@kind"/>
</xsl:attribute>
<xsl:value-of select="." />
</xsl:element>
<xsl:element name="br" />
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
<xsl:template name="id" match = "//*[@kind = 'id']">
<xsl:for-each select="//*[@kind = 'id']">
<xsl:element name="a">
<xsl:attribute name = "class" >
<xsl:text>id</xsl:text>
</xsl:attribute>
<xsl:attribute name = "href" >
<xsl:value-of select="." /><xsl:text>.html</xsl:text>
</xsl:attribute>
<xsl:value-of select="." />
</xsl:element>
<xsl:text> </xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
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