[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: arguments for xsl:call-template
Hi Charly!
I don't understand quite well what you want, because you can do this: <xsl:with-param name="path" select="'/report/histo/bar'" /> but you can do this , <xsl:with-param name="path" select="'/report/histo/@bar'" /> because you are not assigning anything to var. path and also you are doing histogram just once so the 'for-each' has no reason to be. Explain what's the purpose of this template. At 09:38 07/12/01 -0800, you wrote: Hi everyone. I'm a beginner with XSL . Does anyone of you has any idea how to call a template and passing with a node as argument. I'm trying the following . XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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