RE: Finding the maximum number of nodes (Redux)

of the two, i certainly prefer your solution.  It is much simpler to write
and understand.
but as a mental exercise (something to do on my lunch break), i wanted to
see if i could create a single XPath statement that would do the job.  I
nearly bit off more than i could chew!

Now that it "works", i'm just wondering if anyone can verify the logic
behind it.  I'm still not certain that I even understand "why" it works...

Thanks for the code tho -- good stuff.

Marty

> -----Original Message-----
> From: Jörg Heinicke [mailto:joerg.heinicke@xxxxxx]
> Sent: Wednesday, October 03, 2001 10:35 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re:  Finding the maximum number of nodes (Redux)
> 
> 
> > <xsl:attribute name="colspan"><xsl:value-of 
> select="count(tr[count(td)
> &gt;
> > count(following-sibling::tr[count(td) &gt;
> > count(preceding-sibling::tr[last()]/td)]/td)][count(td) &gt;
> > count(preceding-sibling::tr[last()]/td)]/td)"/></xsl:attribute>
> 
> This would be unacceptable for me - who should understand that later?
> 
> Why not something like that:
> 
> <xsl:template match="table">
> <xsl:variable name="cols">
>     <xsl:for-each select="tr">
>         <xsl:sort select="count(td)"/>
>         <xsl:if test="position()=last()">
>             <xsl:value-of select="count(td)"/>
>         </xsl:if>
>     </xsl:for-each>
> </xsl:variable>
> <table border="1">
> <tr>
> <td colspan="{$cols}">Table Header Text</td>
> </tr>
> <xsl:copy-of select="tr"/>
> </table>
> </xsl:template>
> 
> Joerg
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list