[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: problem with proper numbering
Andreas,
If I'm reading this right, you don't want <xsl:number value="position()"/> at all:- position() is no good for your purposes. (Why not, is getting to be a FAQ. Perhaps a little research on what position() actually does would help you: it returns the position of the context node in the current node list, which may have nothing to do with the position of anything in the source document.) My guess without seeing your source data is that you want something like: <xsl:number count="slide|slideset" level="any" format="a"/> or possibly to adopt a different numbering sequence for cards representing slides, and navigation cards generated from slidesets (this may be a cleaner way to go). In any case, your solution is in the other attributes allowed on xsl:number, not the 'value' attribute. Good luck, Wendell At 03:51 AM 10/2/01, you wrote: Hi everybody, I have a XML document I want to translate into a WML document, which should include a table of contents linking to the other pages. So I would like to transform "slidesets" and "slides" into "cards". The problem I have is concerned with the numbering of the "cards". ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ====================================================================== XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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