[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: better way to get a sibling?
> I have XML such as: > > <data> > <row id="1"> > <field name="question_id">5</field> > <field name="answer">1</field> > <field name="total">45</field> > </row> > </data> > > and xpath: > > //field[@name='question_id'][text()=$q_id]/../field[@name='total'] > > if I have $q_id defined as 5, is this the best way to query > the total if given the question id? It's a perfectly reasonable way. If you're doing it a lot, try <xsl:key name="qidk" match="row" use="field[@name=question_id]"/> ...then key('qidk',$q_id)/field[@name='total'] Or even do a pre-transformation from your generic schema to a specific schema: <data> <question row="1" qid="5" answer="1" total="45"/> .... </data> Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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