Re: Access to RowsetSchema attribute

Hi Jeni,

Thanks for your prompt response. I have seen your name
across so many of XSL articles and have visited your
website too, but never thought u would be giving me a
solution to my problem someday.

Thanks again
Gurnandan 
--- Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> wrote: > Hi
Gurnandan,
> 
> > Using the following xml fragment, I need to get
> the value of
> > rs:dbtype attribute, assuming that the current
> context is positioned
> > at the attribute z:row/@c1. How do I do it?
> 
> Presumably you want to know the data type of the c1
> attribute? To get
> that you need the value of the rs:dbtype attribute:
> 
>   @rs:dbtype
> 
> on the s:datatype element:
> 
>   s:datatype/@rs:dbtype
> 
> under the s:AttributeType element whose name
> attribute is 'c1':
> 
>   s:AttributeType[@name =
> 'c1']/s:datatype/@rs:dbtype
> 
> within the s:ElementType within the s:Schema within
> the 'xml' [sic]
> document element:
> 
>  /xml/s:Schema/s:ElementType
>    /s:AttributeType[@name =
> 'c1']/s:datatype/@rs:dbtype
> 
> If you don't know the name of the attribute that you
> want to find the
> data type for, then you can use the name() function
> on the current
> attribute to get it, which would make the path:
> 
>  /xml/s:Schema/s:ElementType
>    /s:AttributeType[@name =
> name(current())]/s:datatype/@rs:dbtype
> 
> If there are lots of s:ElementType elements within
> the s:Schema, then
> you want to choose the one whose name attribute is
> the same as the
> name of the parent of the current attribute node:
> 
>  /xml/s:Schema/s:ElementType[@name =
> name(current()/..)]
>    /s:AttributeType[@name =
> name(current())]/s:datatype/@rs:dbtype
> 
> If you're doing this a lot, you might want to set up
> a key so that you
> can quick access to the relevant s:AttributeType
> element.
>    
> I hope that's the kind of thing you were after,
> 
> Jeni
> 
> ---
> Jeni Tennison
> http://www.jenitennison.com/
> 
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
>  

=====
Cheers!!

Gurnandan

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