[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] forwarding only existing parameter
Hello list. I'm trying to forward parameters from a template to another, only if they are defined, in the most simple way. <template match="foo"> <param name="bar"/> <apply-templates select="."> <with-param name="bar" select="$bar"/> </apply-templates> </template> This one actually forward an empty bar argument when not called with a bar argument, so it's wrong. <template match="foo"> <param name="bar"/> <apply-templates select="."> <if test="$bar"> <with-param name="bar" select="$bar"/> </if> </apply-templates> </template> This one is rejected as not xsl-compliant <template match="foo"> <param name="bar"/> <choose> <when test="$bar"> <apply-templates select="."> <with-param name="bar" select="$bar"/> </apply-templates> </when> <otherwise> <apply-templates select="."/> </otherwise> </choose> </template> This one is OK, but really ugly. Isn't there any other way ? -- Guillaume Rousse <rousse@xxxxxxxxxxxxxx> GPG key http://lis.snv.jussieu.fr/~rousse/gpgkey.html XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|