[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] how to group equal nodes by a it's position()
Hi *, i have next xml: <calls> <call>sme text</call> <call>sme text</call> <call>sme text</call> <call>sme text</call> <call>sme text</call> <call>sme text</call> <call>sme text</call> <call>sme text</call> <call>sme text</call> <call>sme text</call> ..... <call>sme text</call> </calls> i have to group the <call> by it's position() to get <table_1> <call>some text</call> from position 1 to 10 (10 elements in the table_1) <call>some text</call> </table_1> <table_2> <call>some text</call> from position 11 to 25 (15 elements in table_2) </table_2> .... <table_n> <call>some text</call> from position 26 to 40 (15 elements in table_n) </table_n> <table_x> <call>some text</call> from position nnn to mmm (20 elements or less in table_x) </table_x> So I have 3 types of tables, with 10, 15, 20 elements. The number of call nodes in table 1 must be 10 and it must be first 10 elements, the number of call nodes in tables 2 to n must be 15, the number of call nodes in last table must be 20 or less. the number of call elements can be different. eg i have 100 call elements so i have to put in the first table 10 elements, in the tables from 2..6 15 elements and in the last table 15 elements. If i have 106 elements i could put in last table 20 (and make the last table complete) elements end still have ones more element, so i have to create one more table with 15 elements and put in the last table the last 6 elements. are there any solutions of that problem??? thanks for advise Dmitri XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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