Re: catching the last node still satisfying a conditio

Ainsi parlait Michael Kay :
> > I've some difficulties in a XPath expression:
> > In a <foos> list of <foo> i would like to catch:
> > - the last one
> > - having a <bar> child
> > - up to a certain limit
>
> Perhaps:
>
> foos/foo[position() &lt; $limit][bar][last()]
Are successive predicate legal ? And are they evaluated as
foo[position() &lt; $limit AND bar AND last()] or as
(((foo[position() &lt; $limit])[bar])last()]) ?
 
> (But your requirement is not entirely clear)
Sorry, see my exemple in second post.

Note also that i found a solution, quite not very elegant, using a for each 
statement for acting only on last element on filtered set, as shown in my 
third post.

-- 
Guillaume Rousse <rousse@xxxxxxxxxxxxxx>
GPG key http://lis.snv.jussieu.fr/~rousse/gpgkey.html

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