[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] difficulties with exclude-result-prefixes and xsl:copy
Hi. I'm not sure how to do this the correct way. I have the following XML: <xql:result> <Aps:ProductStructure ino:id='4' xmlns:Aps='http://www.foo.com/aps/' id='1'> <Aps:AssemblyName>bar</Aps:AssemblyName> <Aps:AlternateAssemblyName>testc</Aps:AlternateAssemblyName> <Aps:PartNumber>r20359</Aps:PartNumber> <Aps:Name>bar part 4</Aps:Name> <Aps:Description>this is just test data</Aps:Description> <Aps:PartRelationship> <Aps:PreviousAssembly id='0'> <Aps:Name>NSS-10 satellite</Aps:Name> <Aps:QuantityPreviousAssembly>1</Aps:QuantityPreviousAssembly> </Aps:PreviousAssembly> <Aps:Component id='2'> <Aps:Name>bolts</Aps:Name> </Aps:Component> <Aps:Component> <Aps:Name>nuts</Aps:Name> </Aps:Component> </Aps:PartRelationship> <Aps:AsBuilt> </Aps:AsBuilt> </Aps:ProductStructure> </xql:result> And I want it returned to me exactly as it is without the <xql:result> tag and the attribute ino:id after Aps:ProductStructure. I thought I could just use the xsl:copy like so: <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:Aps="http://www.foo.com/aps/" xmlns:ino="http://namespaces.softwareag.com/tamino/response2" xmlns:xql="http://metalab.unc.edu/xql/" exclude-result-prefixes="ino xql"> <xsl:output method="xml" indent="yes" omit-xml-declaration="yes" /> <xsl:template match="* | text() | @*"> <xsl:copy> <xsl:apply-templates select="* | text() | @*"/> </xsl:copy> </xsl:template> </xsl:stylesheet> but this gives me back exactly what I sent in. I'm guessing xsl:copy doesn't get rid of the prefixes and does a straight copy. What is the easiset way for me to get back what I want? Thanks for any help you can give. Amy XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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