[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: copying child nodes n-level deep
Ram Anantha wrote > > Given: > <A> > <B> > <C id="1"> > <D id1="2"> > <E>hello</E> > </D> > </C> > </B> > </A> > > I would like to copy all the elements and their children starting from D. > The logic is, take the grand-child of B (in this case D) and copy it (along > with all its children). The only known element name is B..How can I write a > generic xsl code such that from the following schema: > If you want to perform a deep copy (all elements and their children), use <xsl:copy-of> as opposed to <xsl:copy> which only copies the current element. Selecting the grand-children of the current node can be performed simply with a concatenation of two child::* axis specifiers:- <xsl:template match="B"> <xsl:copy-of select="child::*/child::*"/> </xsl:template> Regards ~Rob -- Rob Lugt ElCel Technology http://www.elcel.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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