[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: namespace declaration when generating a stylesheet
Ta muchly I ended up with a variation on the last suggestion: <xsl:for-each select="$currNode/namespace::*"> <xsl:copy-of select="."/> </xsl:for-each> which does the job splendidly. All the best Mark Seaborne -----Original Message----- From: Michael Kay [mailto:mhkay@xxxxxxxxxxxx] Sent: 27 July 2001 12:56 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: namespace declaration when generating a stylesheet > I am transforming the xml document into a stylesheet via > another stylesheet. > > > The result stylesheet needs any namespace declarations that > were in the > source (where they will be needed). > > How do I get them there (using XSLT)? I am stumped. > Namespace nodes from the source document will be copied into the result document when you copy an element that owns such a namespace node; they will also be generated if you create an element or attribute that refers to the namespace. Apart from that, the only way to get a namespace node into the result document is to do an <xsl:copy[-of]> on a namespace node (and even then, only if the XSLT processor implements the latest XSLT errata). One technique is to create a result tree fragment containing the namespace node, and copy it from there: <xsl:variable name="rtf"> <xsl:element name="dummy" namespace="{$required-namespace}"/> </xsl:variable> <xsl:copy-of select="xx:node-set($rtf)/dummy/namespace::*[.=$required-namespace]"/> Mike Kay Software AG XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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