[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Putting parameter into XPATH expression
James:
At 08:23 PM 6/22/01, you wrote: Hi, Your code is working this way because you are sending strings into your named templates as parameters, not numbers. So the expression <xsl:value-of select="a/b[$Position ]/c"/> is returning a set of nodes including *all* <c> elements (since a non-empty string tests as true, b[$Position] gets you every <b> element in that step). The value of a set of nodes is the value of the first node in the set, hence OneOneOne. <xsl:value-of select="a/b[$Position + 0 ]/c"/> is working the way you want because adding a number (0) to a string ($Position), the processor casts the string to a number as if by the number() function, effectively changing the predicated expression into a number. Far easier would be simply to pass numbers in as parameters, not strings, which you could do by saying <xsl:with-param name="Position" select="1"/> instead of <xsl:with-param name="Position" select="'1'"/> (which you have now). But why not just write a stylesheet that traverses the tree in the normal way? In fact, in your case the null stylesheet <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"/> would get you the output OneTwoThree, since the built-in default templates process the tree recursively, copying text nodes to output. (Well, actually it won't, because of the whitespace floating around your source document, which the processor will also faithfully copy; but it would if you stripped whitespace nodes with an <xsl:strip-space elements="*"/> statement. Try it, you'll see what I mean.) Confused? It's all because of XSLT's powerful and really-not-so-mysterious processing model (that you do have to learn if you want to know how to make things work easily). Want to prevent those text nodes (or any other nodes that might happen to be around) from getting in the way? the stylesheet <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:for-each select="//c"> <xsl:apply-templates/> </xsl:for-each> </xsl:template> </xsl:stylesheet> will get you the output you want. But maybe you want to jump around arbitrarily, controlling the flow order by some logic in the stylesheet, not the source document? Then maybe you need something like what you're writing. If you simply want output that reflects the content of the input in its native order, XSLT is designed to do that anyway with minimal fuss. Regards, Wendell Can someone tell me a better (more correct) way to do this? ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ====================================================================== XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|