Re: How to copy xml which attributes are processed wit

Hi,

> A  pieces of xml is constructed from a series of  **list** elements such as:
> 
> <list a="a0  " b="  b0"/>
> <list a="a1  "  b="b1  "/>
>  ..
> 
> The attributes **a** and **b** are processed with normalize-space function
> to  squeeze out the white-space before taking further transformation
> actions.
> 
> I have difficulty to get copy-of,  normalize-space, attribute work together
> and need your help.

Have you tried the following:

<xsl:template match="list">
   <xsl:copy>
      <xsl:for-each select="@*">
         <xsl:attribute name="{name()}"> 
             <!-- if you have prefixes attributes like xlink:href, you
                  need to add namespace="{namespace-uri()}" -->
            <xsl:value-of select="normalize-space()" />
         </xsl:attribute>
      </xsl:for-each>
      <!-- xsl:apply-templates if your list elements have children to
           be processed -->
   </xsl:copy>
</xsl:template>

Cheers,
Oliver


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