RE: Using position() with sorted node

Thanks for the suggestions on this problem.  Instead of using
position() to identify sorted nodes, I ended up just assigning
unique numerical identifiers (in this case the date stamp) to each
node and accessing them that way.  This makes the processing/sorted
order unimportant.  Unsurprisingly, this is a simple solution for what
seemed like a complicated problem.  Thanks.

Jenny Simpson
SCI Institute
 
 
> On Wed, 14 Mar 2001, Michael Kay wrote:
> 
> > > position() does return the position of the current node in
> > > the current node
> > > list (which is created using an <xsl:apply-templates> or
> > > <xsl:for-each> with
> > > or without any <xsl:sort> elements.) Unfortunately, sorting
> > > the node list
> > > makes accessing the preceding nodes rather tricky since the
> > > preceding and
> > > preceding-sibling axes work on the document and not the
> > > sorted node list.
> > 
> > I think the only way of accessing the preceding node in sorted order is to
> > create a sorted copy of the original data and then process this using the
> > node-set() extension function. Either that, or find a different solution to
> > the requirement.
> > 
> > Mike Kay
> > Software AG
> > 
> > 
> >  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> > 
> 
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list