Re: Serious problems finding syntax

Not sure if I'm reading this correctly, but it looks like your 'if'
expression is evaluating an attribute that does not exist in the source XML
(PREVIOUS_QUERY). Perhaps that should read "PREVIOUS_PAGE"?

Regards,
Frank Neugebauer.

My node goes as follows (removing the standard header info within the XML):
<FOOTER>
	<CONTENT PREVIOUS_PAGE="" NEXT_PAGE="2"></CONTENT>
	<CONTENT PREVIOUS_PAGE="1" NEXT_PAGE="3"></CONTENT>
	<CONTENT PREVIOUS_PAGE="2" NEXT_PAGE="4"></CONTENT>
</FOOTER>

In my XSL I have :
<xsl:for-each select="CONTENT">
	<xsl:if test="@PREVIOUS_QUERY!=''">
		<a><xsl:attribute name="href">default.asp<xsl:value-of
select="@PREVIOUS_QUERY" /></xsl:attribute>Previous Page</a><br/>
	</xsl:if>
</xsl:for-each>

This IF Statement causes NO DATA to appear.   Take out the If statement and
all data appears as it should.

--
Gavin Landon
Karland International
http://www.karland.com/

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

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