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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: select distinct
 I will mention that the elements are not all siblings. Some are, some are further down. The input looks like: You can use the Meunchen method as follows to find all like type attributes in the document scope: <xsl:key name="typeatts" match="x" use="@type"/>
...
<xsl:for-each select="//x[generate-id(.)=
generate-id(key(typeatts,@type))]">
<A href="javascript:element('{@type}')">
<xsl:value-of select="@type"/>
</A>
</xsl:for-each>If you need to subset this within a subtree then you can incorporate into the key value the generated id of the apex of the subtree: <xsl:key name="typeatts" match="x"
use="concat( generate-id(ancestor::y),' ',@type )"/>and change the predicate accordingly. I hope this helps (the fragment above is untested so I may have mistyped). ............. Ken -- G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (Fax:-0995) Web site: XSL/XML/DSSSL/SGML services, training, libraries, products. Book: Practical Transformation Using XSLT and XPath ISBN1-894049-05-5 Article: What is XSLT? http://www.xml.com/pub/2000/08/holman Next public instructor-led training: 2001-01-27,2001-02-21, - 2001-02-27/03-01,2001-03-05/07,2001-04-06/07,2001-05-01 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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