[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: removing duplicate children
From: Kay Michael <Michael.Kay@xxxxxxx> Date: Fri, 1 Dec 2000 11:47:06 -0000 > > I want to iterate thru a list of nodes that I select and only print > > out the unique ones. This is different from what I've seen in the FAQ > > since I want unique values only from the current node and below it. > > This makes it difficult because neither the preceding nor the > preceding-sibling axis gives you the right answer. I'd suggest using > Muenchian grouping with generate-id() of the "owning" node as part of the > key value. See www.jenitennison.com. > > Mike Kay Well, I tried that, several other permutations, and couldn't get anywhere. I did figure out a way to solve the problem though. I use my for-each to build up a string which is then passed to a template I call uniq. The parameter passed in looks something like: |z|a|b|c|a|b|c|b|b|y|z| That is, a "string list" with '|' as a separator. My uniq template uses the string functions substring-before, substring-after, & contains to recursively make that into a unique list. That's a lot of work for such a simple thing (simple in procedural languages). But at least I've got something working now. regards, Cliff Draper Sun Microsystems, Forte Tools (510) 869-3462 or x73462 My opinions may or may not reflect those of my employer. ---------------------------- food for thought --------------------------- The chief cause of problems is solutions. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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