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RE: rendering Xlink from a XML by using XSL

Subject: RE: rendering Xlink from a XML by using XSL
From: "Handren Ahmed" <handren@xxxxxxxxx>
Date: Fri, 10 Nov 2000 11:59:40 +0100
handren
hi!

That was exactly what I meant!
I did write following code but it doesn't work either.
In my xml file I wrote:

<Adress xlink:type="simple" xlink:href="http://www.dsv.su.se"
xlink:show="new"
xmlns:xlink="http://www.w3.org/TR/xlink/"
>Klick here</Adress>

In my xsl file I try to show that link by writing the follwing code:
<xsl:template match="*[@xlink:href]">
	<xsl:value-of select="."/>
</xsl:template>

How can I use Xlink? How can I click on the xlink:-)? I'am very confused.
By the way,what is the purpose of copying the whole XML-file by using a XSL.
Dont you get the same xml file? Why not send over the whole xml-file?

Thank you
Handren A





-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of Eric van der Vlist
Sent: den 9 november 2000 13:27
To: xsl-list@xxxxxxxxxxxxxxxx
Subject: Re: rendering Xlink from a XML by using XSL


Handren Ahmed wrote:

> I would like to use xlink in an applikation, witch I write in XSL. All my
> tries has been faild so far. Anyone could help me out please.

I am not sure that it's what you mean, but I have recently written an
article [1] showing how one can expand links from several linking
technologies (including XLink) with XSLT.

Hope this helps.

Eric

[1] http://www.xml.com/pub/2000/10/04/linking/index.html
--
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Eric van der Vlist       Dyomedea                    http://dyomedea.com
http://xmlfr.org         http://4xt.org              http://ducotede.com
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