[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: sorting the unique elements
> Applying the described approach (the muenchian method) I get > the following > stylesheet: > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:key name="elements" match="*" use="name()" /> > > <xsl:template match="/"> > <xsl:for-each select="//*[generate-id() = > generate-id(key('elements',name())[1])]"> > <xsl:sort select="name()" /> > <xsl:value-of select="name()" /> > </xsl:for-each> > </xsl:template> > > </xsl:stylesheet> Thank you, after trying lots of example codes and lots of methods this (the most elementary) one does the job I wanted. Again, thank you for this solution. David Valera XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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