RE: counting leaf nodes

Hi Perry

<xsl:value-of select="count(descendant::*[not(child::*)])"/>

gives the count of leaf elements below the current element. Or

<xsl:value-of select="count(descendant::su[not(child::*)])"/>

if you only want ot count "su"s.

There may however be more efficient/elegant ways, I'm no guru.

Hope that helps

Mike Ball

 
Application Services Consultant
Software AG UK


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of Perry Roland
> Sent: 30 August 2000 16:03
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: counting leaf nodes
> 
> 
> 
> Hi,
> 
> I need some help with an expression that will count the leaf
> nodes on a given branch.  Let's say I have XML like
> 
> <su><!-- top level -->
>         <su><!-- 2nd level -->
> 		<su><!-- 3rd level -->
> 			<su><!-- 4th level --></su>
> 			<su><!-- 4th level --></su>
> 			<su><!-- 4th level --></su>
> 		</su>
> 	</su>
>         <su><!-- 2nd level -->
> 		<su><!-- 3rd level --></su>
> 		<su><!-- 3rd level --></su>
> 		<su><!-- 3rd level --></su>
> 	</su>
> </su>
> 
> My goal is to be able to output this as an HTML table like
> 
> <TABLE BORDER=1>
> <TR><TD COLSPAN=6>*</TD></TR> <!-- top level -->
> <TR><TD COLSPAN=3>*</TD><TD COLSPAN=3>*</TR> <!-- 2nd level -->
> <TR><TD COLSPAN=3>*</TD><TD>*</TD><TD>*</TD><TD>*</TD></TR> <!-- 
> 3rd level -->
> <TR><TD>*</TD><TD>*</TD><TD>*</TD></TR> <!-- 4th level -->
> </TABLE>
> 
> As I process each su element, in order to calculate the COLSPAN
> attribute, I need to know how many su elements there are below the
> current one that don't have su children themselves.
> 
> Any help is appreciated.
> 
> --
> perry
> 
> 
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> 


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