RE: Strange Sort...

Hello,

I think the easiest way is chaining 2 XSLTs, the first copiest the y values
from children to attributes and the second XSLT sorts the results. 

But I'm curious if one of the xslt-gurus will come up with a solution that
works with one xslt.

bye
Frank

-
Work is the curse of the drinking class. (Oscar Wilde)
Frank Spychalski                   frank@xxxxxxxxxxxxx


->-----Original Message-----
->From: Brian Young [mailto:Brian.Young@xxxxxxx]
->Sent: Wednesday, July 19, 2000 11:51 AM
->To: 'xsl-list@xxxxxxxxxxxxxxxx'
->Subject: Strange Sort...
->
->
->Hello,
->
->I have the following XML hierarchy:
->
-><bucket>
->	<object id="first" x="35" y="10" />
->	<object id="second" x="15" y="58" />
->	<subbucket>
->		<object>
->			<id>third</id>
->			<x>28</x>
->			<y>145</y>
->		</object>
->	</subbucket>
->	<object id="fourth" x="65" y="27" />
-></bucket>
->
->Ok, enough with the funny looks.  I know that the use of id, 
->x, and y should be consistent as either children or an 
->attribute.  ; ).  But, this is what I'm dealing with now, 
->until I can get it changed.
->
->I'd like to be able to sort all four objects based on the 
->value of their "y"s, regardless of whether they are a child 
->or an attribute.  Is that possible?  Doing two sorts, with 
->one being the major and the other the minor will not work.  I 
->think it has to be in one xsl:sort.
->
->Any help is greatly appreciated.
->
->Thanks,
->   Brian Young


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