Re: ### Outputting the "full path". Is this possible ?? ###

Is there a way to get the same effect but via a template? Otherwise for each
element from the source document to the destination document I have to
repeat the code. I would have had that if there were an XSLT standard
function, like xsl:path-of.


Khalid

----- Original Message -----
From: "David Carlisle" <davidc@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxx>
Sent: Friday, May 26, 2000 10:16 AM
Subject: Re: ### Outputting the "full path". Is this possible ?? ###


>   but what if an element contains a sequence of elements, such as
>
>   <departments>
>    <employees>
>    <name>Joe Shmo</name>
>    <name>Bob Shmo</name>
>    </employees>
>   </departments>
>
>
> <xsl:for-each select="(ancestor-or-self::*)"
>      >/*[<xsl:value-of
select="1+count(preceding-sibling::*)"/>]</xsl:for-each>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list