[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Template Select using a param
> When processing these fields i have $id - the row number and value-of . > which is the field I need to pick out. > And I want to display the value of that field within that row. sounds like that is <xsl:apply-templates (or xsl:value-of if it's just character data ) select="/test/ROWSET/ROW[$id]/*[name(.)=current()]" /> ie select the $id'th row and from that select the element node with name equal to the content of the current node. > On Thu, 9 Mar 2000, David Carlisle wrote: I did but if you quote the whole message the digest and list archive gets to look a mess:-) David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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