Matching in IDREFS attributes

Hi,

I am new to this list and, although I searched in the archives and
didn't found any similar request, I may have misread or misunderstood
the specs.

I have XML elements with an ANA attribute of type IDREFS.  I want to
iterate over these refs in XSL and create an hypertext link to each
referenced id.  I am using TEILite so I have something like:

<NAME ANA="CRIMINEL MASCULIN" KEY="jb">Jehan Basset</NAME> ...

<INTERP ID="CRIMINEL" VALUE="Le Criminel"/>
<INTERP ID="MASCULIN" VALUE="Sexe masculin"/>

and I want:

Jehan Basset (<A HREF="#CRIMINEL">1</A>, <A HREF="#MASCULIN">2</A>)

I don't care too much about what is inside the <A>..</A> though.

2nd problem, probably harder: I would also like to have a two-way
linking where the <INTERP ...> points back to all its references.

Here is how I did it with IE5 "context()" extension to XSL:

<xsl:template match="INTERP">
 <xsl:if test="ancestor(TEXT)/BODY//*[@ANA=context()/@ID]">
 <DIV><A>
   <xsl:attribute name="NAME"><xsl:value-of select="@ID"/></xsl:attribute>
   <xsl:value-of select="@VALUE"/>:
  </A><SPAN style="color: blue;">
   <xsl:for-each select="ancestor(TEXT)/BODY//*[@ANA=context()/@ID]">
   <A>
    <xsl:attribute name="HREF">#<xsl:value-of select="@ANA"/>-<xsl:eval>ChildNumber(this)</xsl:eval></xsl:attribute>
    <xsl:value-of select="."/>
   </A>
   </xsl:for-each>
  </SPAN>
 </DIV>
 </xsl:if>
</xsl:template>

However, it doesn't work when @ANA is a list since there is no "member 
of" operator as far as I know in XSLT.

Is there any way to do it with XSLT?

  Jean-Daniel Fekete
  Ecole des Mines de Nantes, 4 rue Alfred Kastler, La Chantrerie,
  BP 20722, 44307 Nantes Cedex 03, France
  Voice: +33-2-51-85-82-08  | Fax: +33-2-51-85-82-49
  Jean-Daniel.Fekete@xxxxxx | http://www.emn.fr/fekete/


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