Re: (simple?) xpath question
Mark, //*[name() = 'a' or name() = 'c'] is the right syntax Xmlizer On Fri, Aug 29, 2008 at 9:57 PM, mark bordelon <markcbordelon@xxxxxxxxx> wrote: > Thanks, Colin, > > > Although the requirements cannot assume how many levels there are between the root node and the desired node, your solution points me to something like this. Does this work? > > > //[name() == "a" and name() == "c"] > > > > > --- On Fri, 8/29/08, Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> wrote: > >> From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> >> Subject: Re: (simple?) xpath question >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx >> Date: Friday, August 29, 2008, 12:22 PM >> >>>>> "Mark" == mark bordelon >> <markcbordelon@xxxxxxxxx> writes: >> >> Mark> All *help*! What is the best way to query >> xml with xpath >> Mark> to get a disjoint nodelist? Specifically i >> want to include >> Mark> just the root node alongwith a descendent >> node. XML: >> Mark> <a> <b> <c> >> </c> </b> </a> XPATH: //c >> Mark> DESIRED RESULT NODELIST: i.e. not this: >> <c> </c> but >> Mark> rather this: <a> <c> >> </c> </a> >> >> One possibility is: >> >> //*[name() != "b"] >> >> It depends on your exact requirements. >> -- >> Colin Adams >> Preston Lancashire
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