Re: (simple?) xpath question
Thanks, Colin, Although the requirements cannot assume how many levels there are between the root node and the desired node, your solution points me to something like this. Does this work? //[name() == "a" and name() == "c"] --- On Fri, 8/29/08, Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> wrote: > From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> > Subject: Re: (simple?) xpath question > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Date: Friday, August 29, 2008, 12:22 PM > >>>>> "Mark" == mark bordelon > <markcbordelon@xxxxxxxxx> writes: > > Mark> All *help*! What is the best way to query > xml with xpath > Mark> to get a disjoint nodelist? Specifically i > want to include > Mark> just the root node alongwith a descendent > node. XML: > Mark> <a> <b> <c> > </c> </b> </a> XPATH: //c > Mark> DESIRED RESULT NODELIST: i.e. not this: > <c> </c> but > Mark> rather this: <a> <c> > </c> </a> > > One possibility is: > > //*[name() != "b"] > > It depends on your exact requirements. > -- > Colin Adams > Preston Lancashire
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