Re: (simple?) xpath question

Mark,

//*[name() = 'a' or name() = 'c']

is the right syntax

Xmlizer

On Fri, Aug 29, 2008 at 9:57 PM, mark bordelon <markcbordelon@xxxxxxxxx> wrote:

Thanks, Colin,


Although the requirements cannot assume how many levels there are between the root node and the desired node, your solution points me to something like this. Does this work?


//[name() == "a" and name() == "c"]




--- On Fri, 8/29/08, Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> wrote:

From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx>
Subject: Re: (simple?) xpath question
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Date: Friday, August 29, 2008, 12:22 PM

"Mark" == mark bordelon

<markcbordelon@xxxxxxxxx> writes:

    Mark> All *help*!    What is the best way to query
xml with xpath
    Mark> to get a disjoint nodelist? Specifically i
want to include
    Mark> just the root node alongwith a descendent
node.    XML:
    Mark> <a>   <b>     <c>
</c>  </b> </a>   XPATH:   //c
    Mark> DESIRED RESULT NODELIST: i.e. not this:
<c> </c>   but
    Mark> rather this: <a>   <c>
</c> </a>

One possibility is:

//*[name() != "b"]

It depends on your exact requirements.
--
Colin Adams
Preston Lancashire