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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: xalan and replace "regex" Play the video Subject: Re: xalan and replace "regex" From: Mansour <mansour77@xxxxxxxxx> Date: Thu, 27 Dec 2007 10:09:48 -0400 I don't know if this would be a good idea at this point. Michael Kay wrote: Is there any way I can use replace with xalan. The replace() function is new in XSLT 2.0, and Xalan only supports XSLT 1.0. Switch to Saxon. Michael Kay http://www.saxonica.com/ Current Thread xalan and replace "regex" Mansour - 27 Dec 2007 09:03:05 -0000 Colin Paul Adams - 27 Dec 2007 09:11:04 -0000 Michael Kay - 27 Dec 2007 10:55:17 -0000 Mansour - 27 Dec 2007 14:10:22 -0000 <= Abel Braaksma - 27 Dec 2007 14:15:32 -0000 Mansour - 27 Dec 2007 14:21:04 -0000 Abel Braaksma - 27 Dec 2007 14:29:31 -0000 Mansour - 27 Dec 2007 15:43:44 -0000 <- Previous Index Next -> RE: xalan and replace "regex", Michael Kay Thread Re: xalan and replace "regex", Abel Braaksma Re: xalan and replace "regex", Abel Braaksma Date Re: Table type output in text, G. Ken Holman Month

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