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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] xalan and replace "regex"
Hello:
Is there any way I can use replace with xalan. I have tried every thing possible but couldn't get it to work: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xalan" xmlns:str="http://exslt.org/strings"> <xsl:import href="str/str.xsl" /> <xsl:template match="program"> <xsl:value-of select="replace(.,'public','<KeyWord> pulic </KeyWord>')" /> </xsl:template> </xsl:stylesheet> I need to scan a piece of java code and be able to highlight the words based on their meaning. Anyone had luck with xalan regex ?? or analyze-string ??
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