Re: Accessing node-sets by index with position()

<xsl:for-each select="$set">
   <xsl:text>Iteration #</xsl:text>
   <xsl:value-of select="position()"/>
   <xsl:text> is '</xsl:text>
   <xsl:value-of select="$set[position()]"/>

<xsl:text>'&#10;</xsl:text>
</xsl:for-each>
...
So I know that I the second node in the node set is correct, but position() won't get me to it. Does anyone know how I can fix this problem?

T:\ryan>type ryan.xml
<info>
   <field>111</field>
   <field>222</field>
</info>

T:\ryan>type ryan.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                version="1.0">

<xsl:template match="/">
  <xsl:variable name="set" select=".//field"/>

<xsl:for-each select="$set">
   <xsl:text>Iteration #</xsl:text>
   <xsl:value-of select="position()"/>
   <xsl:text> is '</xsl:text>
   <xsl:variable name="for-each-position" select="position()"/>
   <xsl:value-of select="$set[$for-each-position]"/>
   <xsl:text>'&#10;</xsl:text>
</xsl:for-each>

</xsl:stylesheet>
T:\ryan>saxon ryan.xml ryan.xsl
Iteration #1 is '111'
Iteration #2 is '222'

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