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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Accessing node-sets by index with position()
 I am trying to iterate through a list of nodes in a node-set by index using the position() function, and I am running into some difficulties. XML snippet ----- <info> <field>111</field> <field>222</field> </info> XSLT snippet ----- <!-- $set is the node-set containing the two <field> elements --> <xsl:for-each select="$set"> <xsl:text>Iteration #</xsl:text> <xsl:value-of select="position()"/> <xsl:text> is '</xsl:text> <xsl:value-of select="$set[position()]"/> <xsl:text>' </xsl:text> </xsl:for-each> This gives the following output Iteration #1 is 111 Iteration #2 is 111 It seems as though the position() function is working, but when I try to get at the 2nd node by index, it goes to the first node. If I replace $set[position()] with $set[2], I get the following... Iteration #1 is 222 Iteration #2 is 222 So I know that I the second node in the node set is correct, but position() won't get me to it. Does anyone know how I can fix this problem? Any help is greatly appreciated. Thanks, --Ryan XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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